将选择的图片显示在listview中，并显示filename，path和type_.NET_编程开发_程序员俱乐部

class="brush:csharp;gutter:true;"> if (openFileDialog1.ShowDialog() == DialogResult.OK)
            {
                listView1.Items.Clear();
                string[] files = openFileDialog1.FileNames; //定义一个数组，获取选择的文件
                string[] fileinfo = new string[3];  //定义一个数组，用于存储文件信息
                for (int i = 0; i < files.Length; i++)  //遍历文件数组
                {
                    string path = files[i].ToString();  //获取文件路径
                    //截取文件名字
                    string fileName = path.Substring(path.LastIndexOf("\\") + 1, path.Length - 1 - path.LastIndexOf("\\"));
                    //截取文件类型
                    string fileType = fileName.Substring(fileName.LastIndexOf(".") + 1, fileName.Length - 1 - fileName.LastIndexOf("."));
                    fileinfo[0] = fileName;
                    fileinfo[1] = path;
                    fileinfo[2] = fileType;
                    ListViewItem lvi = new ListViewItem(fileinfo);
                    listView1.Items.Add(lvi);

                }
           }

　　注释：ListView1, View 属性为Details

             OpenFileDialog1,Multiselect属性为true