java时间大小比较_JAVA_编程开发_程序员俱乐部

摘自： http://blog.sina.com.cn/s/blog_9844f5d901012ra8.html

方法一：

DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try

{

    Date d1 = df.parse("2004-03-26 13:31:40");

    Date d2 = df.parse("2004-01-02 11:30:24");

    long diff = d1.getTime() - d2.getTime();

    long days = diff / (1000 * 60 * 60 * 24);

}

catch (Exception e)

{

}

方法二：

   SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

   java.util.Date now = df.parse("2004-03-26 13:31:40");

   java.util.Date date=df.parse("2004-01-02 11:30:24");

   long l=now.getTime()-date.getTime();

   long day=l/(24*60*60*1000);

   long hour=(l/(60*60*1000)-day*24);

   long min=((l/(60*1000))-day*24*60-hour*60);

   long s=(l/1000-day*24*60*60-hour*60*60-min*60);

   System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");

方法三：

   SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

   java.util.Date begin=dfs.parse("2004-01-02 11:30:24");

   java.util.Date end = dfs.parse("2004-03-26 13:31:40");

   long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒

   long day1=between/(24*3600);

   long hour1=between%(24*3600)/3600;

   long minute1=between600/60;

   long second1=between`/60;

   System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");



====================================================

java 比较时间大小

String s1="2008-01-25 09:12:09";

String s2="2008-01-29 09:12:11";

java.text.DateFormat df=new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java.util.Calendar c1=java.util.Calendar.getInstance();

java.util.Calendar c2=java.util.Calendar.getInstance();

try{

　　c1.setTime(df.parse(s1));

　　c2.setTime(df.parse(s2));

}catch(java.text.ParseException e){

　　System.err.println("格式不正确");

}

int result=c1.compareTo(c2);

if(result==0)

　　System.out.println("c1相等c2");

else if(result<0)

　　System.out.println("c1小于c2");

else

　　System.out.println("c1大于c2");