最近需要频繁的登录4A系统,可是移动效率如此低下,申请个账号好几个月了还不行。
无奈,好多同事共用同一账号,但是每次都需要将手机号改为自己的。好麻烦。 今天加班,事情不多。写个脚本替我做吧。class="java">public class Modify4ATempMobile{ private static HttpClient client = null; public static void main(String[] args) throws Exception { String loginURL = "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=getPwdProtectBeforeLoginForTempMobile"; String checkURL = "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=checkPwdProtectBeforeLoginForTempMobile"; String updateURL = "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=setTempMobile"; Map<String, String> param = new HashMap<String, String>(); param.put("userId", "crm_xxx"); param.put("authCode", "xxx12345"); System.out.println(doPost(loginURL, param)); param.clear(); param.put("question", "xx"); param.put("answer", "xx"); System.out.println(doPost(checkURL, param)); param.clear(); param.put("tempmobile", "13814027174"); System.out.println(doPost(updateURL, param)); } public static String doPost(String url, Map<String, String> parameters) throws IOException { //使用同一个client,保持session if(client == null){ client = getHttpClient(); } PostMethod method = new PostMethod(url); if(parameters != null && !parameters.isEmpty()){ NameValuePair[] list = new NameValuePair[parameters.size()]; int i = 0; Entry<String, String> entry = null; for(Iterator<Entry<String, String>> iterator = parameters.entrySet().iterator(); iterator.hasNext(); ){ entry = (Entry<String, String>) iterator.next(); list[i++] = new NameValuePair(entry.getKey(), entry.getValue()); } method.setRequestBody(list); } client.executeMethod(method); return method.getResponseBodyAsString(); } public static HttpClient getHttpClient(){ HttpClient client = new HttpClient(); //代理设置,不用可以去掉 client.getHostConfiguration().setProxy("proxy.bmcc.com.cn", 8080); client.getParams().setAuthenticationPreemptive(true); //如果代理需要密码验证,这里设置用户名密码 client.getState().setProxyCredentials(AuthScope.ANY, new UsernamePasswordCredentials("ngcrm_xxx","xxx")); //end 代理 client.getHttpConnectionManager().getParams().setConnectionTimeout(0); client.getHttpConnectionManager().getParams().setSoTimeout(0); return client; } }? 跑了下,没有问题,完美解决问题。
@echo off setlocal enabledelayedexpansion set work_path=D:\Work-bj\crm_bj\lib d: cd %work_path% for %%F in (%work_path%\apache\*.jar) do call :addcp %%F for %%F in (%work_path%\appframe\*.jar) do call :addcp %%F for %%F in (%work_path%\other\*.jar) do call :addcp %%F for %%F in (%work_path%\runtime\*.jar) do call :addcp %%F set classpath= .;D:/Work-bj/crm_bj/html/WEB-INF/classes;%CLASSPATH% java com.asiainfo.test.Modify4ATempMobile pause :addcp echo %1 SET CLASSPATH=%CLASSPATH%;%1? 4.改用VBS试试 做完后觉得不错,可是想想太土了。能不能简单点呢。突然就想用vbs试试。虽然没写过,不过不就是代码嘛,试试。 ?
Const userId="crm_xxx" Const passwd="xxx12345" Const question="xxx" Const answer="xxx" Const tempmobile="13814027174" Dim http Set http = CreateObject("Msxml2.XMLHTTP") http.open "POST", "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=getPwdProtectBeforeLoginForTempMobile", False http.setRequestHeader "CONTENT-TYPE","application/x-www-form-urlencoded" http.send "authCode=" & passwd & "&userId=" & userId http.open "POST", "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=checkPwdProtectBeforeLoginForTempMobile", False http.setRequestHeader "CONTENT-TYPE","application/x-www-form-urlencoded" http.send "question=" & question & "&answer=" & answer http.open "POST", "http://4aportal.bmcc.com.cn/userset/pwdmanage.do?method=setTempMobile", False http.setRequestHeader "CONTENT-TYPE","application/x-www-form-urlencoded" http.send "tempmobile=" & tempmobile? 5.继续完善下
Set ie = CreateObject("InternetExplorer.Application") ie.visible=true ie.Navigate "http://4aportal.bmcc.com.cn/" do until 4=ie.readyState do until 4=ie.readyState waittime = waittime + 200 if waittime > 15000 then exit do Loop Loop if 4<>ie.readyState then ie.quit WScript.quit end if set dom = ie.document set form = dom.getElementById("logonForm") form.all("name").value = userId form.all("pwd").value = passwd '短信登录 'form.all("button4").click() '语音登录 form.all("button5").click()? 自动登陆完成后,我就意识到,能不能将整个过程都做成可视化的,自动的呢。毕竟后台改数据,出问题也不好定位。经过研究,最终结果如下。
'请修改信息为需要的信息。 '用户名 Const userId = "crm_xxx" '密码 Const passwd = "xxx12345" '密保问题 Const question = "xxx" '密保答案 Const answer = "xxx" '临时手机号 Const tempmobile = "13814027174" '短信登录:1 语音登录:2 Const logintype = 2 ' 如果打开默认的ie呢 Set ie = CreateObject("InternetExplorer.Application") ie.Visible = true ie.Top = 0 ie.Left = 0 ie.Navigate "http://4aportal.bmcc.com.cn/iam/belogin/login_findpwdproduct_tempmobile.jsp" wait4ieready() '发送alt+空格+x最大化 Set WshShell = WScript.CreateObject("WScript.Shell") WshShell.SendKeys "%+(' 'x)" ie.document.getelementByid("userId").value = userId ie.document.getelementByid("authCode").value = passwd ie.document.getelementByid("confirm").click() wait4ieready() ie.document.getElementById("answer").value = answer ie.document.getElementById("confirm").click() wait4ieready() ie.document.getElementById("tempmobile").value = tempmobile ie.document.getElementById("confirm").click() wait4ieready() ie.document.getElementById("skip").click() wait4ieready() ie.document.getElementById("name").value = userId ie.document.getElementById("pwd").value = passwd if logintype = 1 then '短信登录 form.all("button4").click() else '语音登录 ie.document.getElementById("button5").click() end if sub wait4ieready() do while ie.ReadyState <> 4 or ie.busy wscript.sleep 200 loop end sub?? 总结 这样好多了,不得不说,看起来好玩多了。