Android获取指定URL的内容_移动开发_编程开发_程序员俱乐部

定义一个读取输入流的工具类

package cn.mzba.utils;

import java.io.ByteArrayOutputStream;
import java.io.InputStream;

public class StreamTool {
	/**
	 * 读取输入流数据
	 * @param is
	 * @return
	 * @throws Exception
	 */
	
	public static byte[] readStream(InputStream is)throws Exception{
		ByteArrayOutputStream os = new ByteArrayOutputStream();
		byte[] buffer = new byte[2048];
		int len = 0;
		while((len = is.read(buffer)) != -1){
			os.write(buffer,0,len);
		}
		is.close();
		return os.toByteArray();
	}
}

?根据指定的路径获取网络上的内容

?

package cn.mzba.utils;

import java.io.File;
import java.io.FileOutputStream;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;


public class ImageService {

	public static void main(String[] args) throws Exception{
		String path = "http://images.enet.com.cn/2007/1024/46/1917978.jpg";
		URL url =  new URL(path);
		HttpURLConnection conn = (HttpURLConnection)url.openConnection();
		conn.setRequestMethod("GET");
		conn.setConnectTimeout(5 * 1000);
		if(conn.getResponseCode() == 200){
			InputStream is = conn.getInputStream();
			byte[] data = StreamTool.readStream(is);
			File file = new File("sex.jpg");
			FileOutputStream fs = new FileOutputStream(file);
			fs.write(data);
			fs.close();
		}else{
			System.out.println("请求失败");
		}
		
	}
}