JSP中带条件的查询分页_JAVA_编程开发_程序员俱乐部

[b]对于带条件查询的分页，用到的主要是session,在提交时判断是不是第一次提交，如果是session.getAttribute("condition") ==null 则为空，同时创建一个新的这里我们用Map 存放健值对，并将此对象的放入session。
前面我们可以这样写
      <fieldset>
    	<legend>物料搜索</legend>
    	<form action="GoodsAction?type=selectSome" method="post">
    		物料名字:<input type="text" name='goodsName'  value="${condition['goodsName']} " />
    	          物料类型<input type="text" name="goodsType"  value="${condition['goodsType'] }"/><br/>
    	        <input type="submit"/>
    	          <hr/>
    	</form>
    </fieldset>
    <table border=1>
    	<tr>
    		<th>名字</th>
    		<th>数量</th>
    		<th>价格</th>
    		<th>类型</th>
    		<th>供应商</th>
    	</tr>
    	<c:forEach var ="temp" items="${page.list}">
			<tr>
				<td>${temp.name }</td>
				<td>${temp.count }</td>
				<td>${temp.price }</td>
				<td>${temp.type_id }</td>
				<td>${temp.provider_id}</td>
			</tr>    	
    	</c:forEach>
    </table>
	    <jsp:include page="../page.jsp">
    		<jsp:param value="GoodsAction" name="name"/>
    		<jsp:param value="selectSome" name="type"/>
    	</jsp:include>
---------------------------
后台
String pageNum = request.getParameter("pageNum");
		String goodsName = request.getParameter("goodsName");
		String goodsType = request.getParameter("goodsType");

		HttpSession session = request.getSession();
		Map<String, String> condition = (Map<String, String>) session.getAttribute("condition");
		if (condition == null) {
			condition = new HashMap<String, String>();
			session.setAttribute("condition", condition);
		}
		if (goodsName != null) {
			condition.put("goodsName", goodsName);
		}
		if (goodsType != null) {
			condition.put("goodsType", goodsType);
		}
		if (pageNum == null)
			pageNum = "1";

		PageInfo p = new PageInfo(Integer.parseInt(pageNum), 10, "t_s_goods");
		dao.getAll(p, condition);
		request.setAttribute("page", p);
		request.getRequestDispatcher("goods/goods_list.jsp").forward(request,response);[/b]